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A farmer moves along the boundary of a square field of side 10minute in 40second . what will be the magnitude of displacement of farmer at the end of 2minute and 20second |
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Answer» Answer:The answer, the displacement is 10√2 m Explanation: Look, let's note all the given info, SIDE of the field = 10m Time taken to walk along the boundary of the square field = 40s Time given to calculate the displacement = 2 min 20 s= 2×60 + 20 =140s Total distance walked by him in 140s = 40s=> 40m 140s => 'x' Therefore, x = 140×40/40= 140 m That means, distance covered by him in time 2 min 20s = 140m Perimeter of the field = 10×4 = 40 m No. Of ROUNDS taken = 140/40 = 4.5 That means, he didn't complete the 4th time. Now IMAGINE, make a right angled triangle, from the point the FARMER started to the point where he ENDED ine the second side. Look at the diagram, attached here. So, it's a right angled triangle, By Pythagoras theorem, (Side) ^2 = √(10) ^2 +(10) ^2 Side2 = √100 + 100=√200 Side = 10√2m ..... ( taking square root of both sides) { here side means side of a right angled triangle} Displacement = final - initial position = 10√2-0= 10√2m Hope it helps.... :) If it does, don't forget to appreciate my efforts by adding me as the brainliest! :) |
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