A farmer moves along the boundary of a square field of side 10 m in 40 seconds what will be the magnitude of displacement of the farmers at the end of 2 minutes 20 seconds

A farmer moves along the boundary of a square field of side 10 m in 40

1.	A farmer moves along the boundary of a square field of side 10 m in 40 seconds what will be the magnitude of displacement of the farmers at the end of 2 minutes 20 seconds
Answer» Total distance = perimeter of square= 4×10m=40m. Time taken=40s Therefore, total time taken by farmer =2min 20seconds=140 seconds Therefore,140/40=3.5 Therefore the farmer completes 3 and half round of the square,i.e.,if he starts from A he reaches point c after 2 min 20 seconds. Therefore,DISPLACEMENT is AC. To find AC ,assume a triangle ADC inside a square . In triangle ADC AC square is equal to AD square +DC square AC square = (10)2+ (10)2 AC square= 100+100 AC square= 200 =10√2m.

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A farmer moves along the boundary of a square field of side 10 m in 40 seconds what will be the magnitude of displacement of the farmers at the end of 2 minutes 20 seconds

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