1.

A drunkard moves on a straight road such that he takes 7 steps forward and 2 steps backward in each cycle. If the stride length of each step is 1 feet and the drunkard moves with a speed 2 feet/s in forward direction and 4 feet/s in backward direction, then the time after which the drunkard will fall into a pit 11 feet further from his starting point is 6 s 2.5 s 7 s 2 s

Answer»

the CORRECT ANSWER is 7S



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