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`A` drop of water of volume `V` is pressed between the two glass plates so as to spread to an area. `A`. If `T` is the surface tension, the normal force required to separate the glass plates isA. `(TA^(2))/(V)`B. `(2TA^(2))/(V)`C. `(4TA^(2))/(V)`D. `(TA^(2))/(2V)` |
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Answer» Correct Answer - B Force required to separate the glass plates `F=(2AT)/(t) xx (A)/(A) = (2TA^(2))/((Axxt)) = (2TA^(2))/(V)` |
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