A drop of water of volume V is pressed between the two glass plates so as to spread on area A. If T is the surface tension, the normal force required to separate the glass plates is :

A drop of water of volume V is pressed between the two glass plates so

1.	A drop of water of volume V is pressed between the two glass plates so as to spread on area A. If T is the surface tension, the normal force required to separate the glass plates is :
Answer» Solution :PRESSURE difference = `T/R=T/(t//2)=(2T)/t`, FORCE = `(2T)/TA` But V = At or t = `V/A,THEREFORE"Force"=(2TA^(2))/V`