1.

A driver accelerates his car at the rate of 2.4m/s^2 and then at the rate of 1.6m/s^2. What will be the ratio of the two forces exerted by the engine in the two cases?

Answer» F1 be the FORCE in FIRST case
F1=m×(2.4)

DE be the force in the SECOND case
F2=m×(1.6)

\frac{f1}{f2}  =  \frac{3}{2}
so F1:F2=3:2


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