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A driver accelerates his car at the rate of 2.4m/s^2 and then at the rate of 1.6m/s^2. What will be the ratio of the two forces exerted by the engine in the two cases? |
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Answer» F1 be the FORCE in FIRST case F1=m×(2.4) DE be the force in the SECOND case F2=m×(1.6) so F1:F2=3:2 |
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