A DNA segment has a total of 1500 nucleotides, out of which 410 are Gu

1.	A DNA segment has a total of 1500 nucleotides, out of which 410 are Guanine containing nucleotides. How many pyrimidine bases this DNA segment possesses?
Answer» According to Chargaff's rule \(\frac{A}{G}\) = \(\frac{T}{G}\) = 1 G = G, G = 410, hence C = 410 G + C = 410 + 410 = 820 So, A + T = 1500 - 820 = 680 A = T, so T = \(\frac{680}{2}\) = 340 So, pyrimidines = C + T = 410 + 340 = 750

A DNA segment has a total of 1500 nucleotides, out of which 410 are Guanine containing nucleotides. How many pyrimidine bases this DNA segment possesses?

Answer»

According to Chargaff's rule

\(\frac{A}{G}\) = \(\frac{T}{G}\) = 1

G = G, G = 410, hence C = 410

G + C = 410 + 410 = 820

So, A + T = 1500 - 820 = 680

A = T, so T = \(\frac{680}{2}\) = 340

So, pyrimidines = C + T

= 410 + 340 = 750