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A disc having radius `R` is rolling without slipping on a horizontal (`x-z`) plane. Centre of the disc has a velocity `v` and acceleration `a` as shown. Speed of point `P` having coordinates `(x,y)` isA. `(vsqrt(x^(2)+y^(2)))/R`B. `(vsqrt(x^(2)+(y+R)^(2)))/R`C. `(vsqrt(x^(2)-(y-R)^(2)))/R`D. none |
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Answer» Correct Answer - A `omega=v/R` Distance of P from origin. `r=sqrt(x^2+y^2)` Origin is instantaneous of rotation. So, `v_P=omegar=(vsqrt(x^2+y^2))/R` |
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