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A die is thrown 6 times. If getting an odd number is a success, what is the probability of(i) 5 successes?(ii) at least 5 successes?(iii) at most 5 successes? |
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Answer» Here, `n = 6` P(success)` p = 3/6=1/2 ` P(failure)` q = 3/6 =1/2` (i)P(5 successes) `= n_(C_5)p^5q^1 = 6_(C_5)(1/2)^5(1/2)` `=6**1/32**1/2 = 6/64 = 3/32` (ii)P(At least 5 successes) `= P(X=5)+P(X=6) = 3/32+6_(C_6)(1/2)^6=3/32+1/64 = 7/64` (iii)P(at most 5 successes) `= 1-P(X=6) = 1-6_(C_6)(1/2)^6 = 1-1/64 = 63/64` |
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