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A deer sees a tiger 100m away and starts running away from it at the speed of 15 mps.The tiger sees the deer 5 seconds later and pursues it at the speed of 40 mps. How muchlater will the tiger catch the deer? |
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Answer» Step-by-step explanation: Spee of deer = 15m/sTime =5 secDISTANCE traveled by deer in 5 sec when tiger do not see the deerDistance = speed × time= 15 × 5=75 mNow to caught the deer, the tiger has to cover extra 75 m as it starts to run 5sec LATE till thatthe deer has been COVERED 75M of extra distance.So the total distance which tiger has to cover =100 +75=175 mSpeed of tiger = 40m/sTime taken = Distance /speed= 175/40= 4.3 secTiger will take 4.3 sec to caught the deer |
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