A dealer sold a camera for Rs. 1080 gaining 1/8 of its cost price. F

1.	A dealer sold a camera for Rs. 1080 gaining 1/8 of its cost price. Find:-(i) the cost price of the camera, and (ii) the gain per cent earned by the dealer.
Answer» (i) Let × be the CP of Camera. SP of Camera = x + 1x/8 = 1080 × + x/8 = 1080 9x/8 = 1080 x = (1080 × 8) / 9 = 960. So, the Cost Price (CP) of camera is Rs.960. (ii) Gain = SP – CP = 1080 – 960 = 120 \(Gain\%=\frac{Gain\times100}{CP}\) \(=\frac{120\times100}{960}\) = 12.5%

A dealer sold a camera for Rs. 1080 gaining 1/8 of its cost price. Find:-(i) the cost price of the camera, and (ii) the gain per cent earned by the dealer.

Answer»

(i) Let × be the CP of Camera.

SP of Camera = x + 1x/8 = 1080

× + x/8 = 1080

9x/8 = 1080

x = (1080 × 8) / 9

= 960.

So, the Cost Price (CP) of camera is Rs.960.

(ii) Gain = SP – CP

= 1080 – 960

= 120

\(Gain\%=\frac{Gain\times100}{CP}\)

\(=\frac{120\times100}{960}\)

= 12.5%