1.

A dealer sold a camera for Rs.1080 gaining 1/8 of its cost price.Find:(¡)the cost price of the camera.(¡¡)The gain per cent earned by the dealer.

Answer» HII..
Here is your ANSWER..

Solution:-
Let the CP be x
Gain =1/8 of Cp
= > \frac{1}{8} of \: x \\ = > \frac{x}{8}
Selling PRICE=1080
SP=Cost Price+Gain
= > 1080 = x + \frac{x}{8} \\ = > 1080 = \frac{8x + x}{8} \\ = > 1080 = \frac{9x}{8}
= > x = \frac{1080 \times 8}{9} \\ = > x = 960
Therefore,
Cost Price =₹960

Now,
Gain =x/8
= > \frac{x}{8} \\ = > \frac{960}{8} \\ = > 120
We KNOW that,
gain\% = \frac{gain}{cp} \times 100 \\ = > \frac{120}{960} \times 100 \\ = > 12.5
Hence,
Gain is 12.5℅

Hope it helps UH...✌️✌️✌️


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