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A cylindrical vessel open at the top is `20cm` high and `10 cm` in diameter. A circular hole of cross-sectional area `1cm^(2)` is cut at the centre of the bottom of the vessel. Water flows from a tube above it into the vessel at the rate of `10^(2)cm^(3)//s`. The height of water in the vessel under steady state is (Take `g=10m//s^(2))`.A. `20cm`B. `15cm`C. `10cm`D. `5cm` |
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Answer» Correct Answer - D In steady state, Volume flow rate entering the vessel =volume flow rate leaving the vessel `:. Q=av=a sqrt(2gh)` or `h=(Q^(2))/(2ga^(2))` `=((10^2)^(2))/((2xx1000)(1)^(2))=5cm`. |
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