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A cylindrical vessel of diameter 12 cm contains 800π cm3 of water. A cylindrical glass piece of diameter 8.0 cm and height 8.0 cm is placed in the vessel. If the bottom of the vessel under the glass piece is seen by the paraxial rays (see figure 18-E6), locate its image. The index of refraction of glass is 1.50 and that of water is 1.33. |
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Answer» r= 6cmr1=4cmh1=8cmlet H be the height of WTAER columnThe volume of the cylindrical water column after the glass piece is π r² h= 800π + π r1² h1r² h= 800 + r1² h16² h = 800+ 4² x 8h= 800+ 128/36= 929/36= 25.7 cmThere are TWO shifts DUE to glass slab and waterΔt1=[1-(1/μ)xt=[1- (1/3/2)]x 8=2.26cmΔt1=[1-(1/μ)xt=[1-(1/4/3)(25.7-8)= 4.44cm∴Total shift = 2.66+4.47= 7.1cm |
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