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A cylindrical rod whose height is 8 times of its radius is melted and recast into spherical balls of same radius. The number of balls will be :A. 4 B. 3 C. 6 D. 8 |
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Answer» Option : (C) Volume of a sphere = \(\frac{4}{3}\)πr3 Volume of a cylinder = πr2h Given, cylindrical rod whose height is 8 times of its radius is melted and recast into spherical balls of same radius. Let the number of such balls be ‘a’. ⇒ π × r2 × 8r = a × \(\frac{4}{3}\)π × r3 ⇒ a = 6 |
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