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A cylindrical rod having temperature `T_(1)` and `T_(2)` at its ends. The rate of flow of heat is `Q_(1) cal//sec`. If all the linear dimensions are doubled keeping temperature constant, then rate of flow of heat `Q_(2)` will beA. `4 Q_(1)`B. `2 Q_(1)`C. `(Q_(1))/(4)`D. `(Q_(1))/(2)` |
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Answer» Correct Answer - B (2) `(Q_(1))/(Q_(2)) = (R_(2))/(R_(1)) = (2 l //K . Pi (2 r)^(2))/(l..K . Pi r^(2)) = 1//2` `Q_(2) = 2Q_(1)` |
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