A cylindrical conductor of length l and uniform area of cross-section A has resistance R. Another conductor of length 2l and resistance R made up of the same material will have area of crosssection equal to :(A) A/2(B) 3A/2(C) 2A(D) 3Aplease do explain.I will mark it as brainliest.

A cylindrical conductor of length l and uniform area of cross-section

1.	A cylindrical conductor of length l and uniform area of cross-section A has resistance R. Another conductor of length 2l and resistance R made up of the same material will have area of crosssection equal to :(A) A/2(B) 3A/2(C) 2A(D) 3Aplease do explain.I will mark it as brainliest.
Answer» istance of a wire can be EXPRESSED as R=ρ AL A=ρ RL where,ρ - Resistivity - the factor in the resistance which takes into account the NATURE of the MATERIAL is the resistivityL - Length of the CONDUCTORA - Area of a cross-section of the conductor.From this relation, we OBSERVE that the length is directly proportional to the resistance and the area of cross-section is inversely proportional to the resistance.In this case, the length of the conductor is doubled (2L) and so the resistance will be 2R. For the resistance to remain the same as R, the area of cross-section is also doubled as 2A.

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A cylindrical conductor of length l and uniform area of cross-section A has resistance R. Another conductor of length 2l and resistance R made up of the same material will have area of crosssection equal to :(A) A/2(B) 3A/2(C) 2A(D) 3Aplease do explain.I will mark it as brainliest.​

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A cylindrical conductor of length l and uniform area of cross-section A has resistance R. Another conductor of length 2l and resistance R made up of the same material will have area of crosssection equal to :(A) A/2(B) 3A/2(C) 2A(D) 3Aplease do explain.I will mark it as brainliest.