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A cylindrical bar with 200mm diameter is being turned with a tool having geometry 0o−9o−7o−8o−15o−30o−0.05inch (Coordinate system, ASA) resulting in a cutting force Fc1. If the tool geometry is changed to 0o−9o−7o−8o−15o−0o−0.05inch (Coordinate system, ASA) and all other parameters remain unchanged, the cutting force changes to Fc2. Specific cutting energy (in J/mm3) is Uc=U0(t1)−0.4, where Uo is the specific energy coefficient, and t1 the uncut thickness in mm. The value of percentage change in cutting force Fc2. i.e., (Fc2−Fc1Fc1)×100,, is(round off to one decimal place). |
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Answer» A cylindrical bar with 200mm diameter is being turned with a tool having geometry 0o−9o−7o−8o−15o−30o−0.05inch (Coordinate system, ASA) resulting in a cutting force Fc1. If the tool geometry is changed to 0o−9o−7o−8o−15o−0o−0.05inch (Coordinate system, ASA) and all other parameters remain unchanged, the cutting force changes to Fc2. Specific cutting energy (in J/mm3) is Uc=U0(t1)−0.4, where Uo is the specific energy coefficient, and t1 the uncut thickness in mm. The value of percentage change in cutting force Fc2. i.e., (Fc2−Fc1Fc1)×100,, is |
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