A cylinder was filled with gaseous mixture containing so and n2 the ra

1.	A cylinder was filled with gaseous mixture containing so and n2 the ratio of the partial pressure in cylinder is
Answer» Answer: We KNOW that, In a gaseous MIXTURE, the Partial PRESSURE of individual gas is the product of the total pressure and the mole fraction of the gas Partial Pressure = Total pressure * mole fraction We also know that, PV = nRT Where, n is number of moles Partial pressure of CO= Mass of CO / MOLECULAR mass of CO = Mass of CO / 28 Partial pressure of N2= Mass of N2 / Molecular mass of N2 = Mass of N2/ 28 Ratio of partial pressure = (Mass of CO / 28) / (Mass of N2 / 28) Since Both the masses are equal, Ratio = 1:1 Hope it helps you.......

A cylinder was filled with gaseous mixture containing so and n2 the ratio of the partial pressure in cylinder is

Answer»

Answer:

We KNOW that, In a gaseous MIXTURE, the Partial PRESSURE of individual gas is the product of the total pressure and the mole fraction of the gas

Partial Pressure = Total pressure * mole fraction

We also know that, PV = nRT

Where, n is number of moles

Partial pressure of CO= Mass of CO / MOLECULAR mass of CO = Mass of CO / 28

Partial pressure of N2= Mass of N2 / Molecular mass of N2 = Mass of N2/ 28

Ratio of partial pressure = (Mass of CO / 28) / (Mass of N2 / 28)

Since Both the masses are equal, Ratio = 1:1

Hope it helps you.......