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a cylinder of fixed capacity 67.2 litres contains helium gas at st.p.the amount of heat required to raise the temperature of the gas by 15 degree celsius is(R=8.31 j/mol/k) a.520j b.560.9j c.620j d.621.2j plz explain with solution |
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Answer» V = 67.2 litres of Helium at STP ΔT = 15⁰K1 mole of an ideal gas occupies 22.4 litres at STP. So number of moles of Helium gas n = 67.2/22.4 = 3we know that γ = ratio of specific heats for an ideal MONO atomic gas = 5/3 C_p = heat capacity at constant pressure for a mono atomic gas = 5/2 R C_v = heat capacity at constant VOLUME for a mono atomic gas = 3/2 R Change in internal energy = n C_v ΔT = 3 * 3/2 * 8.31 J/mol/°K * 15°K = 560.925 Joules There is no change in the volume and hence no work done in heating the gas by 15 DEG. Heat supplied = change in internal energy = 560.925 Joules |
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