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A cylinder of a material is `10 cm` long and has a cross-section of `2 cm^2`. If its resistance along the length be `20 Omega`, what will be its resistivity in numbers and units ? |
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Answer» Correct Answer - `4 Omega cm` `rho = (RA)/(l) = ((20 Omega)(2 cm^2))/(10 cm) = 4 Omega cm`. |
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