1.

A cylinder of 20.0 L capacity contains 160 g oxygen gas at `25^(@)C`. What mass of oxygen must be released to reduce the pressure of the cylinder to 1.2 atm ?

Answer» Number of moles of oxygen gas present initially in the cylinder`=(160g)/(32"g mol"^(-1))=5" moles"`
To calculate the number of moles now present, we have P=1.2 atm, T=298 K, V=20.0L
Applying the relation, PV=nRT, we have `n=(PV)/(RT)=(1.2" atm "xx20.0" L")/(0.0821" L atm " K^(-1)mol^(-1)xx298" K")=0.98" mol"`
`:.` Number of moles of `O_(2)` required to be released =5-0.98=4.02 mol
or Mass of `O_(2)` required to be released `=4.02xx32" g"=128.64" g"`


Discussion

No Comment Found

Related InterviewSolutions