A cylinder containe 20 kg of N_(2) gas (M= 28 kg K^(-1) mol^(-1)) at a [ressire pf 5 atm. The mass of hydrogen (M = 28 kg K^(-1) mol^(-1)) at a pressure of 3 atm contained in the same cylinder at same temperature is

A cylinder containe 20 kg of N_(2) gas (M= 28 kg K^(-1) mol^(-1)) at a

1.	A cylinder containe 20 kg of N_(2) gas (M= 28 kg K^(-1) mol^(-1)) at a [ressire pf 5 atm. The mass of hydrogen (M = 28 kg K^(-1) mol^(-1)) at a pressure of 3 atm contained in the same cylinder at same temperature is
Answer» <P>1.08 kg 0.86 kg 0.68 kg 1.68 kg Solution : `V/T=(nR)/p` V and T for both CASES in same. Hence `(n_(1))/(p_(1))=(n_(2))/(p_(2))or (m_(1))/(p_(1)M_(1))=(m_(2))/(p_(2)M_(2))` or `""m_(2)(p_(2)M_(2))/(p_(1)M_(1)).m_(1)=((3)(2))/((5)(28)).20=0.86kg`