1.

A cylinder and a cone have equal radii of their bases and equal heights. If their curved surface area are in the ratio 8:5, show that the radius of each is to the height of each as 3:4.​

Answer»

Given :-

  • Cylinder and a cone have equal RADII of their bases and equal heights.
  • CSA ratio = 8 : 5 .

To Show :-

  • Radius : Height = 3 : 4 . ?

FORMULA used :-

  • CSA of cone = π * r * l
  • l = Slant Height = √(r² + h²) => l² = (r² + h²)
  • CSA of cylinder = 2 * π * r * h

Solution :-

LET radius of cone & cylinder = r

Height of cone & cylinder = h .

slant height of cone = l

A/q,

(CSA of cylinder) / (CSA of cone ) = 8/5

→ (2 * π * r * h ) / ( π * r * l ) = 8/5

π & r will be CANCEL,

(2h / l) = 8/5

→ h / l = 4/5

Squaring both sides ,

(h/l)² = (4/5)²

→ h²/ l² = 16/25

Putting = ( + ) in LHS,

h²/(r² + h²) = 16/25

Cross - Multiply,

25h² = 16(r² + h²)

→ 25h² = 16r² + 16h²

→ 25h² - 16h² = 16r²

→ 9h² = 16r²

→ r²/h² = 9/16

Square - root both sides ,

r/h = 3/4.

Hence,

r : h = 3 : 4. (Ans).



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