A cyclist driving at 36km/hr stops his cycle and in 2s, by application

1.	A cyclist driving at 36km/hr stops his cycle and in 2s, by application of breaks. calculate retardation. (or negative acceleration).
Answer» ANSWER: ACCELERATION = $\frac{v-u}{t}$ = 0-10/2. =-5 m/s^2

A cyclist driving at 36km/hr stops his cycle and in 2s, by application of breaks. calculate retardation. (or negative acceleration).

Answer»

ANSWER:

ACCELERATION = $\frac{v-u}{t}$

= 0-10/2.

=-5 m/s^2

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A cyclist driving at 36km/hr stops his cycle and in 2s, by application of breaks. calculate retardation. (or negative acceleration).​

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A cyclist driving at 36km/hr stops his cycle and in 2s, by application of breaks. calculate retardation. (or negative acceleration).