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A cyclic process ABCDA has 4 steps. Heats involved in all processes are given by QAB=4800 Joules, QBC=1000 Joules, QCD=500 Cal and QDA=−1000 Cal. Find efficiency of engine based on above cyclic process. (1 Cal = 4.2 Joules) |
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Answer» A cyclic process ABCDA has 4 steps. Heats involved in all processes are given by QAB=4800 Joules, QBC=1000 Joules, QCD=500 Cal and QDA=−1000 Cal. Find efficiency of engine based on above cyclic process. (1 Cal = 4.2 Joules) |
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