A current of dry air was passed through a solution of 2.5 gram of unkn – InterviewSolution

1.	A current of dry air was passed through a solution of 2.5 gram of unknown volatile subs†an ce X in 100 gram of water and then through water around the loss in weight of the former was 1.25 and that of the latter was 0.05 calculate 1) the mole fraction of solute in the solution 2) molecular weight of the solute
Answer» A current of dry air was passed through a solution of 2.5 gram of unknown volatile subs†an ce X in 100 gram of water and then through water around the loss in weight of the former was 1.25 and that of the latter was 0.05 calculate 1) the mole fraction of solute in the solution 2) molecular weight of the solute

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