1.

A current of 5 ampere is flowing through a wire of 60cm in length? This wire is kept perpendicular to a uniform magnetic field of 20 tesla? Calculate the value of force acting on this wire

Answer»

When a wire that carries a current I is placed in a magnetic field of intensity B it will experience a magnetic force which is given by the formula

F = qvBsinθ

where  v is the velocity of charges, here v = l/t

so the force on the wire will be F = q/tlBsinθ

F= qvBsinθ

since the wire is kept perpendicular to the field the angle will be 90⁰ the  current flowing through the wire I = 5A

length of the wire l = 60 cm = 0.60 m

the magnetic field intensity B = 20T

substituting the given values the force acting on the wire is 

F = 5 x 0.60 x 20 sin90 = 60N



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