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A current of 5 ampere is flowing through a wire of 60cm in length? This wire is kept perpendicular to a uniform magnetic field of 20 tesla? Calculate the value of force acting on this wire |
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Answer» When a wire that carries a current I is placed in a magnetic field of intensity B it will experience a magnetic force which is given by the formula F = qvBsinθ where v is the velocity of charges, here v = l/t so the force on the wire will be F = q/tlBsinθ F= qvBsinθ since the wire is kept perpendicular to the field the angle will be 90⁰ the current flowing through the wire I = 5A length of the wire l = 60 cm = 0.60 m the magnetic field intensity B = 20T substituting the given values the force acting on the wire is F = 5 x 0.60 x 20 sin90 = 60N |
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