a current of 4 ampere was passed for 1.5 hours through a solution of copper sulphate when 3.2 g of copper was deposited. Calculate the current efficiency.

a current of 4 ampere was passed for 1.5 hours through a solution of c

1.	a current of 4 ampere was passed for 1.5 hours through a solution of copper sulphate when 3.2 g of copper was deposited. Calculate the current efficiency.
Answer» CURRENT EFFICIENCY = 45 %.Step-by-step explanation :Given that,Current = 4 amperes.Time = 1.5 hours = 1.5 × 60 × 60 s = 5400 seconds.Also,MOLAR mass of copper = 63.5 g/mol.For deposition of Cu, the reaction is :-According to the reaction, 1 mole of Cu requires CHARGE = 2 F = 2 × 96500 C.∴ 3.2 g Cu will require charge :-Now, quantity of electricity PASSED :-⇒ Current × Time ⇒ 4 × 5400 ⇒ 21600 C.