Saved Bookmarks
| 1. |
A current of `2.68A` is passed for one hour through an aqeous solution of `CuSO_(4)` using copper electrodes. Select the correct statement (s) from the followingA. increase in mass of cathode=3.174 gB. decrease in mass of anode=3.174 gC. no change in masses of electrodesD. the ratio between the change of masses of cathode and anode is 1:2 |
|
Answer» Correct Answer - A,C `{:("At Cathode:"Cu^(2+) + 2e^(-) to Cu(S)),("At Anode:"Cu(s) to Cu^(2+)+2e^(-)):}` Increase in mass of cathode = decrease in mass in Anode =`(2.68xx3600)/96500xx63.5/2=3.174 g` |
|