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A current of `(2.5+-0.05)` A flows through a wire and develops a potential difference of `(10+-0.1)` volt. Resistance of the wire in ohm, isA. `4+-0.12`B. `4+-0.04`C. `4+-0.08`D. `4+-0.02` |
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Answer» `R=(10)/(2.5)=4+-DeltaR` `DeltaR=0.03xx4=0.12` |
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