1.

A current of `1 A` is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in `16` seconds would be roughly :A. `10^20`B. `10^10`C. `10^18`D. `10^23`

Answer» Correct Answer - A
As `Q = I t = (1 A)(16 s) = 16 C, n = (Q)/( e) = (16 C)/(1.6 xx 10^-19 C) = 10^20`.


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