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A current of `1 A` is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in `16` seconds would be roughly :A. `10^(20)`B. `10^(16)`C. `10^(18)`D. `10^(23)` |
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Answer» Correct Answer - A Given, current, I = 1 A Time, t = 16 s Number of electrons n = ? We know that, Current, `I = (Q)/(t) = ("ne")/(t)` `" "[because e = "Charge of an electron" = 1.6 xx 10^(-19)C and Q = "ne"]` `rArr` `" "n = (It)/(e) = (1 xx 16)/(1.6 xx 10^(-19)) = 10^(20)` |
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