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A current `I = 10 sin (100pi t)` amp. Is passed in first coil, which induces a maximum e.m.f of `5pi` volt in second coil. The mutual inductance between the coils is-A. 10 mHB. 15 mHC. 25 mHD. 5 mH |
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Answer» Correct Answer - D Let `I = I_(0) sin omegat`, where `I_(0) = 10, omega = 100 pi` then `epsilon = M(dl)/(dt)` `= M(d)/(dt) I_(0) sin omegat` `= M I_(0)omega cos omegat` `therefore epsilon_("max") = MI_(0)omega` `5pi = M xx 10 xx 100pi` `M = 5mH` |
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