Saved Bookmarks
| 1. |
A cubical vessel of height `1` m is full of water. What is the workdone in pumping water out of the vessel?A. 1250 JB. 5000 JC. 1000 JD. 2500 J |
|
Answer» Correct Answer - B The volume of water contained in the vessel would be equal to `V=I^(3)=(1m)^(3)`. Assuming water to be pure so the density of water would be equal to `d = 1000 kgm^(-3)`, hence the mass of water containded in the vessel would be equal to m = Vd = 1000 kg. Thus, the work done would be equal to `W=mgh=1000xx10xx1/2=5000 j` |
|