A cubical block of wood of edge 0.2m weighing 6.4kgf floats on water.

1.	A cubical block of wood of edge 0.2m weighing 6.4kgf floats on water. Find the depth of immersion. Given,density of water 1000kg/m^3.
Answer» Given:- Water DENSITY is 1000 kg/m^3 Edge of Cuboidal BLOCK = 0.2m Weight of Block = 4.6kgf To FIND:- DEPTH the block merged. SoluTion:- As, $→\;{\sf{Edge×Depth×Density = Weight}}$ So, $→\;{\sf{0.2m×0.2 m ×D × 1000 kg/m^3 = 6.4 kgf}}$ Where D is depth of immersion. $→\;{\sf{D = 6.4kg/(1000x 0.2x 0.2) }}$ $→\;{\Large{\red{\bf{Depth = 0.16 m}}}}$ Hope It Helps You ✌️

A cubical block of wood of edge 0.2m weighing 6.4kgf floats on water. Find the depth of immersion. Given,density of water 1000kg/m^3.

Answer»

Given:-

Water DENSITY is 1000 kg/m^3
Edge of Cuboidal BLOCK = 0.2m
Weight of Block = 4.6kgf

To FIND:-

DEPTH the block merged.

SoluTion:-

As,

$→\;{\sf{Edge×Depth×Density = Weight}}$

So,

$→\;{\sf{0.2m×0.2 m ×D × 1000 kg/m^3 = 6.4 kgf}}$

Where D is depth of immersion.

$→\;{\sf{D = 6.4kg/(1000x 0.2x 0.2) }}$

$→\;{\Large{\red{\bf{Depth = 0.16 m}}}}$

Hope It Helps You ✌️

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