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A cubical block of side 'a' moving with velocity v on a horizontal smooth plane as shown. It hits a ridge at point o. The angular speed of the block after it hits o is

Answer»

ular speed of the BLOCK after it HITS o is  ω=3v / 4aExplanation:τ = r x FLi = LfL = r x p = (a/2 J x MVi) = - MVa/2 NI = Ma^2 / 6Lf = IωConserving angular momentum about O (just before and just after ) is mv a/2 = [ma^2 / 6. ma^2 /2] ωω=3v / 4aThus the angular speed of the block after it hits o is  ω=3v / 4aAlso learn moreA ball of MASS 0.1kg is SUSPENDED by a string 30cm long. Keeping the string taut, the ball describes a horizontal circle of radius 15cm. Find the angular speed ?brainly.in/question/12380618



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