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A cubical block of side 7 cm is surmounted by a hemi-sphere. What is the greatest diameter the hemispherecan have? Find the surface area of solid. |
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Answer» side of cube = 7cmdiameter of hemisphere=7radius=7/2 cmsurface area of solid= (TSA of cube - 1 surface area )+ SA of hemisphere={ 6(7)^2-(7)^2} + 2×22/7×7/2×7/2= 5×49+ 11×7= 405+77= 482 cm^2 the greatest diameter that the hemisphere can have is 7cm and surface area of solid will be =(tsa of cube - πr^2)+CSA of hemisphere edge of the cube=7cmlargest diameter=7cmr=d/2r=3.5cmCSA of solid=5×(side)²+CSA of hemisphere +(area of base of square - area of base of hemisphere)CSA=5 × 49 + 2×22/7×(3.5)²+(7×7- 22/7×(3.5)²CSA= The cube has side = 7cm. So, the hemisphere has greatest diameter = 7cmr = 7cm/2 CSA of hemisphere = 2πr²= 2 * 22/7 * 7cm/2 * 7cm/2= 77cm² TSA of cube= 6*(side)²= 6 * (7cm)²= 6 * 49cm²= 294cm² The hemisphere enclosed a circular top part of the circle, when surmounted on it. Area of Enclosed region= πr²= 22/7 * 7cm/2 * 7cm/2= 38.5cm² TSA of solid = (CSA of hemisphere) + (TSA of cube) - (Area of enclosed region) = 77cm² + 294cm² - 38.5cm²= 332.5cm² 482cm^2 is correct answer edge of the cube =7cmlargest diameter =7cm r=d/2r=3.5cmcsa of solid answer of your questions 482 cm^2 iska answer 7000 hoga side of cube is 7 cm greatest diameter that hemisphere can have is 7 cmradius of hemisphere is 7/2 cmsurface area of soild is ( TSA of cube-pie r^2) + CSAof hemisphere the greatest diameter is 7 greatest diameter of hemisphere is 7cm.surface area of solid is 332.5 side of cube = 7cm diameter of hemisphere=7radius=7/2 cmsurface area of solid=(TSA of cube - 1surface area )+ SA of hemisphere ={ 6 (7)^2-(7^2} + 2×22/7×7/2×7/2=5×49+ 11×7=405+77=482 cm^2 The cube has side=7 cm So, the hemisphere has a greater diameter=7cmr=7cm/2 CSA of hemisphere=2πr²=2*22/7*7cm/2*7cm/2=77cm² TSA of cube=6*(side)I=6*(7cm)²=6*49cm=294cm² The hemisphere enclosed a circular top part of the circle, when surmounted on it.Area of enclosed region= πr²= 22/7*7cm/2*7cm/2=38.5cm²TSA of solid(CSA of hemisphere)+(TSA of cube)-(Area of enclosed region)=77cm² +294cm² -38.5cm²=332.5cm² greatest diameter will be 7and total area will be 482 cm squares okkk 482 cm is the answer i think side of cube 7cm diameter of hemisphere=7 radius=7/2 cm surface area of solid= (tsa of cube 1 surface area )+ sa of hemisphere ={6(7)^2-(7)*2}+ 2x22/7x7/2x7/2 5x49+11x7 405+77 482 cm^2 Actual area of the pot=2πr2+5l2=2×22/7×3.5×3.5+5×7×7=44/7×3.5×3.5+5×49=44×0.5×3.5+245=44×1.75+245=77+245=322cm2 322+10.5=332.5cm2area of square=l2 =7×7=49area of circle=πr2 =22/7×3.5×3.5=22/7×0.5×3.5=22×1.75=38.5=49-38.5=10.5cm2 |
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