1.

A cube of side b has a charge q at each of its vertices. The electric field due to this charge distribution at the centre of the cube is

Answer»

`(Q)/(b^(2))`
`(q)/(2B^(2))`
`(32q)/(b^(2))`
zero

Solution :There is an equal charge at diagonally opposite corner. The fields due these at the CENTRE cancel out. Therefore, the NET field at the centre is zero.


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