A cube of 9 cm edge is immersed completely in a rectangular vessel con

1.	A cube of 9 cm edge is immersed completely in a rectangular vessel containing water. If the dimensions of the base are 15 cm and 12 cm, find the rise in water level in the vessel.
Answer» Given, Edge of cube = 9 cm Dimension of base of rectangular vessel = 15cm × 12cm Volume of cube = 9 × 9 × 9 = 729 cm³ Area of base of vessel = 15 × 12 = 180 cm² So, rise of water in vessel = \(\cfrac{volume\,of\,cube}{area\,of\,base}\) \(=\cfrac{729}{180}\) = 4.05 cm

A cube of 9 cm edge is immersed completely in a rectangular vessel containing water. If the dimensions of the base are 15 cm and 12 cm, find the rise in water level in the vessel.

Answer»

Given,

Edge of cube = 9 cm

Dimension of base of rectangular vessel = 15cm × 12cm

Volume of cube = 9 × 9 × 9 = 729 cm³

Area of base of vessel = 15 × 12 = 180 cm²

So, rise of water in vessel = \(\cfrac{volume\,of\,cube}{area\,of\,base}\)

\(=\cfrac{729}{180}\) = 4.05 cm