1.

a cricketer Hits a ball with a velocity 25m/s at 60° above horizontal.how far above the ground it passes over a fielder 50m from the bat ?​

Answer»

ATE The HORIZONTAL velocity of the ball will be vcosø or 25cos60 this AMOUNT will be 12.5m/s ALONG X axis Then50/12.5=4seconds before the ball is thrown by the cricketer.The VERTICAL height will be H(4)=g/2(4)²+25sin60(4)=-4.9(16)+21.25(4)=8.2025m as height of the ball after 4secHOPE THIS HELPS YOUPLEASE FOLLOW ME ✌️MARK ME AS BRAINLIST



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