a cricket ball of mass 50 gram moving with a velocity of 0.75 metre pe

1.	a cricket ball of mass 50 gram moving with a velocity of 0.75 metre per second is stopped by a player in 0.75 second what is the force applied by the player to stop the ball
Answer» Step-by-step EXPLANATION: mass of the body = 50 gram VELOCITY = 0.75 /s INITIAL velocity = 0.75 final velocity = 0 ACCELERATION = final velocity - initial velocity /time = 0-0.75/0.75 = -1m/s force = m×a force = 50×-1 = -50 Newton

a cricket ball of mass 50 gram moving with a velocity of 0.75 metre per second is stopped by a player in 0.75 second what is the force applied by the player to stop the ball

Answer»

Step-by-step EXPLANATION:

mass of the body = 50 gram

VELOCITY = 0.75 /s

INITIAL velocity = 0.75

final velocity = 0

ACCELERATION = final velocity - initial velocity /time

= 0-0.75/0.75

= -1m/s

force = m×a

force = 50×-1

= -50 Newton

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a cricket ball of mass 50 gram moving with a velocity of 0.75 metre per second is stopped by a player in 0.75 second what is the force applied by the player to stop the ball​

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a cricket ball of mass 50 gram moving with a velocity of 0.75 metre per second is stopped by a player in 0.75 second what is the force applied by the player to stop the ball