1.

A crane operated by an electric motor has a mass of 500kg.it raises a load of 300 kg vertically at a steady speed 0. 2m/s. Assume resistance to be constants at the 1200N.what is the power required To raise. The load.

Answer»

of the crane + WEIGHT of the load = 500 + 300 = 800 kggravitational FORCE due to the weight = 800 * g =  800 * 10  NEWTONS.     Resistance to lifting action of the crane  like friction etc. = 1,200 N  Total force needed to lift the load with a velocity 0.2 m/s = 8,000 + 1,200 Newtonspower needed to lift the load with a velocity (uniform)      P = F * V  =  9, 200 N * 0.2 m/sec =  1, 840 Watts



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