Saved Bookmarks
| 1. |
a cottage industry produce a certain number of pottery articles in a day it observed on a particular day that the cost of production of each article (in rupee) was 3 more than twice the number of article produced on that day if total cost of production on that day was rupee 90 find the number of articles produced and cost of each article |
|
Answer» ong>Answer: 15 RUPEES Step-by-step explanation: We know that Total COST of production = Number of articles PRODUCED × Cost of article Given total cost of production =Rs.90 and Cost of production of each article (in rupees) was 3 more than TWICE and number of articles produced on that day Let the number of articles =x Hence, Cost of article =2x+3 Now, Total cost of production = Number of articles produced × Cost of article 90=x(2x+3) 2x 2 +3x−90=0 2x 2 +15x−12x−90=0 x(2x+15)−6(2x+15)=0 (x−6)(2x+15)=0 x=6, 2 −15
But x cannot be negative as number of articles is not negative Hence, x=6 ∴ Number of articles =6 And Cost of article =2x+3 =2(6)+3 =12+3 =Rs.15 |
|