1.

A copper wire when bent in the form of a square, enclosed an area of 121 m^2. If the wire is bent to form a circle, the area enclosed by it would be-

Answer»

A of square = s^2
121=s^2

\sqrt{121 } = s
s = 11
P of square = 4s
P = 4 × 11
Length of wire is equal to PERIMETER
therefore, length of wire = 44m
perimeter of square = perimeter of circle
circumference of circle =
2\pi \: r
44= 2 \times \frac{22}{7} \times r
44 \times 7 = 2 \times 22 \times r
44 \times 7 = 44 \times r
7 = r
area of circle =
\pi {r}^{2}
= \frac{22}{7} \times 7 \times 7
22 \times 7
= 154m
therefore area of circle = 154 m^2


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