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A copper wire of cross-sectional area 0.5 m m^(2) carries a current of 0.2A. If the free electron density of copper is 8.4xx10^(28)m^(-3) then compute the drift velocity of free electrons. |
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Answer» Solution :The relation between DRIFT velocity of electrons and current a wire of cross-sectional area A is `v_(d)=(1)/(n eA)=(0.2)/(8.4xx10^(28)xx1.6xx10^(-19)xx0.5xx10^(-6))` `v_(d)=0.03xx10^(-3)MS^(-1)` |
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