Saved Bookmarks
| 1. |
A copper wire has diameter of 0.5 mm and resistivity of 1.6 into 10 to the power minus 6 ohm cm how much of this wire would be required to make a 10 ohm coil |
|
Answer» R = 0.25×10^-3 m A = 3.14× 0.25 × 10^-3 = 0.785 m^2 P = -6 × 10^-2 R = 10 ohm R = p _l_ A 10 = -6×10^-2 × _l_ 0.785 × 10^-3 10 = -7.64 × 10 × L l = 1/-7.64 l = 1.303 m |
|