A copper block of mass 1 Kg slides down on a rough inclined plane of inclination 37^(0) at a constant speed. Find the increase in temperature of the block as it slides down through 60 cm assuming that the loss in mechanical energy goes to the copper block as thermal energy? (specific heat of copper = 420 J Kg^(-1)K^(-1) and g = 10ms^(-2))

A copper block of mass 1 Kg slides down on a rough inclined plane of i

1.	A copper block of mass 1 Kg slides down on a rough inclined plane of inclination 37^(0) at a constant speed. Find the increase in temperature of the block as it slides down through 60 cm assuming that the loss in mechanical energy goes to the copper block as thermal energy? (specific heat of copper = 420 J Kg^(-1)K^(-1) and g = 10ms^(-2))
Answer» Solution :Loss in gravitational PE = Thermal ENERGY: MG sin `370 = ms Deltatheta` `implies 10 XX 3/5 = 420 xx Deltatheta` , Change in temperature `Deltatheta = 8.6 xx 10^(-30)C`