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A convex mirror has radius of curvature 3 metre if the object is located 5m from the mirror find the position nature and size of the imageplz its urgent

Answer» ANS)
Radius r = -3m
therefore focal length = -3/2m
= 1.5 m
object DISTANCE U = 5M
image distance V =?
we know,
\frac{1}{v} + \frac{1}{u} = \frac{1}{f} \\ \frac{1}{v} + \frac{1}{ - 5} = \frac{1}{1.5} \\ \frac{1}{v} = \frac{1}{ - 1.5} - \frac{1}{ - 5} \\ \frac{1}{v} = - 59 - (1.5) \div 7.5 \\ \frac{1}{v} = \frac{ - 6.5}{7.5} \\ v = \frac{7.5}{ - 6.5} \\ v = - 1.15 \\


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