A converging beam of light rats falls on a concave mirrir of focal len

1.	A converging beam of light rats falls on a concave mirrir of focal length 20 cm. They appear to meet at a point which is 30 cm away from pole and 10 cm below principal axis. Find the location and nature of image formed
Answer» Explanation: Given:- Focal Length ,f = -20cm Image distance ,v = -30cm Image height ,hi = -10 cm (below the principal axis.) To Find:- Location & Nature of Image Formed Solution:- As it is given that the mirror is converging mirror . When light RAYS fall on the mirror its forms an image 30 cm away from the POLE. And also the image formed by concave mirror is real & Inverted . Firstly, we calculate the image distance Using Mirror FORMULA • 1/v + 1/u = 1/f Substitute the value we get → -1/30 + 1/u = 1/(-20) → -1/30 + 1/u = -1/20 → 1/u = -1/20 + 1/30 → 1/u = -3+2/60 → 1/u = -1/60 → u = -60 cm Hence, the object distance is 60 cm in front of mirror. Now, Calculating the Magnification • m = hi/ho = -v/u Substitute the value we get → -10/ho = -(-30)/-60 → -10/ho = -30/60 → -10/ho = -1/2 → ho = 20 cm Hence, the height of the object is 20 cm. Nature of Image :- Real & Inverted .

A converging beam of light rats falls on a concave mirrir of focal length 20 cm. They appear to meet at a point which is 30 cm away from pole and 10 cm below principal axis. Find the location and nature of image formed

Answer»

Explanation:

Given:-

Focal Length ,f = -20cm
Image distance ,v = -30cm
Image height ,hi = -10 cm (below the principal axis.)

To Find:-

Location & Nature of Image Formed

Solution:-

As it is given that the mirror is converging mirror . When light RAYS fall on the mirror its forms an image 30 cm away from the POLE. And also the image formed by concave mirror is real & Inverted .

Firstly, we calculate the image distance

Using Mirror FORMULA

• 1/v + 1/u = 1/f

Substitute the value we get

→ -1/30 + 1/u = 1/(-20)

→ -1/30 + 1/u = -1/20

→ 1/u = -1/20 + 1/30

→ 1/u = -3+2/60

→ 1/u = -1/60

→ u = -60 cm

Hence, the object distance is 60 cm in front of mirror.

Now, Calculating the Magnification

• m = hi/ho = -v/u

Substitute the value we get

→ -10/ho = -(-30)/-60

→ -10/ho = -30/60

→ -10/ho = -1/2

→ ho = 20 cm

Hence, the height of the object is 20 cm.
Nature of Image :- Real & Inverted .